21x^2(2x-3)+41x(2x-3)+10(2x-3)

how do I factor the expression - completely
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1 Answer

You have to distribute the outside value across the parenthesis.

21x^2(2x-3)+41x(2x-3)+10(2x-3)

42x^3 - 63x^2 + 82x^2 - 123x +20x - 30

42x^3 + 19x^2 - 103x - 30

by Level 10 User (55.7k points)

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