3tan^3 - tan x = 0

Solve the equation in the the interval < x < 2 pi
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1 Answer

I assume you mean 3tan3(x)-tan(x)=0.

tan(x)(3tan2(x)-1)=0,

tan(x)=0⇒x=0+nπ; (n is an integer)

tan2(x)=1/√3⇒x=±π/6+nπ.  

by Top Rated User (1.1m points)

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