pls help me in my homework thanks everyone
asked Jun 28, 2016 in Calculus Answers by Paul

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3 Answers

There's a sort of cutoff point at x=-2 when f(x)=0. For x>-2 f(x) is increasing, and for x<-2 it's decreasing. At exactly x=-2 there's a saddle-point where the gradient is flat (horizontal) so x is nether increasing or decreasing.

answered Jun 29, 2016 by Rod Top Rated User (429,040 points)
let x and y from R:

(x + 2)^3 - (y + 2)^3 = (x-y)((x+2)^2 + (x+2)(y+2) + (y+2)^2)
((x+2)^2 + (x+2)(y+2) + (y+2)^2)>= ((x+2)^2 - 2 |(x+2)(y+2)| + (y+2)^2)>=0
than
(x + 2)^3 - (y + 2)^3 >= 0 => (x-y)>=0 => x >= y

than f is increasing in R

or

h(x) = x + 2 is increasing and g(x) = x^3 is increasing than f = goh(x) is increasing
answered Jun 29, 2016 by norrye
Function f(x) = (x+2)^3 is not increasing and decreasing
answered Jun 30, 2016 by John Marsh Level 8 User (30,400 points)
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