Problem: what is the surface area of 8 inchs 3 inchs and 4 inchs?
find the surface area of 8 inchs,3 inchs and 4 inchs
This has to be a three dimensional object known as a hexahedron. Consider
it to be a cube that has been squashed in two of the directions. It has
six faces. Two of them are 8 in. by 4 in. Two are 8 in. by 3 in. The last
two are 3 in. by 4 in. We calculate the area of each face and add them together
to arrive at the total surface area.
(3 in. * 4 in.) * 2 = 24 sq. in.
(8 in. * 4 in.) * 2 = 64 sq. in.
(8 in. * 3 in.) * 2 = 48 sq. in.
24 sq. in. + 64 sq. in. + 48 sq. in. = 136 sq. in.