Find the coordinates of the center and radius of a circle by equation x^2+y^2+10x-6y+18=0
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1 Answer

x² + y² – 10x + 6y + 18 = 0 

x² – 10x + y² + 6y + 18 = 0 

x² – 10x + 25 - 25 + y² + 6y + 9 - 9 + 18 = 0 
(x-5)² + (y+3)² -16 = 0 

(x-5)² + (y+3)² = 16 
(x-5)² + (y+3)² = 4² 
Center at (5,-3) radius = 4 

Part 2 
1. Complete the square for x and y 
2. Put in the format for a circle. (x-h)² + (y-k)² = r², center at (h,k) with radius = r

by Level 10 User (57.4k points)

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