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Find the equation in general form of the circle with center at the origin and r = 3.

The general equation of a circle is given by,

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the centre of the circle and r is the radius of the circle.

We have (h, k) = (0, 0) (i.e. the origin) and r = 3

Substituting for the above,

(x - 0)^2 + (y - 0)^2 = 3^2

Answer: x^2 + y^2 = 9

by Level 11 User (81.5k points)

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