Angles of polygons
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Let S=number of sides. The angles at the centre are each 360/S these being the vertex angles of S triangles making up the polygon. The triangles are isosceles, so the other angles are (180-360/S)/2=90-180/S. Two of these angles in adjacent triangles form the interior angle of the polygon, so 180-360/S=144. So 36=360/S and S=360/36=10. The polygon has ten sides.

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