Monica is 7 years older than cheena.Aroma is 2 times younger than monica.if the sum of their ages is 58,what is the age of each child?
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Let the ages be M, C, A for Monica, Cheena, Aroma.

M=C+7, A=M/2.

M+C+A=58.

C+7+C+(C+7)/2=58, 4C+14+C+7=116

5C+21=116, 5C=116-21=95, C=95/5=19. Cheena is 19. M=19+7=26, Monica is 26 and Aroma is 26/2=13.

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