Find the possible values of x between -180° to 360°

If cos x=sin200° then find the possible values of x between -180° to 360°.
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For any angle A sinA=cos(90-A).

If A=200, sin200=cos(90-200)=cos(-110)=cos(110).

Therefore x is -110 or 110. But -110 is also 360-110=250. So the solutions is x=-110, 110, 250.
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