A rectangle with sides parallel to the axes has vertices at (3,-2) and (-1,-7). a. Find the coordinates of the other two vertices. b. Find the area of the rectangle.
in Geometry Answers by Level 1 User (340 points)

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1 Answer

(a) The other two vertices are at (-1,-2) and (3,-7) so combining the given coordinates.

(b) The area is (3-(-1)) * (-2-(-7))=4*5=20 sq units.

by Top Rated User (1.1m points)
How did you get the two other coordinates? Can you show methe solutions pls

You were given the coordinates of a diagonal (3,-2) and (-1,-7). All you do is swap the x and y coords between the two points. So you take the x coord of the first point and join it to the y coord of the second point: (3,-7); then you take the y coord of the first point and join it to the x coord of the second point: (-1,-2). You can do this because you're told that the sides of the rectangle are parallel to the axes. Hey presto! It's a lot easier and clearer if you draw a picture.

To find the area, you find length and width by finding the difference between the x coords and y coords, then multiply length and width to get the area. It's the absolute difference you need, that is, the difference that gives you a positive number. On the picture you can confirm the length and width by counting the squares. Remember, when you subtract a negative number it's the same as adding: for example, 3-(-1)=3+1=4.

I got it. Thankyouu

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