A point P has the coordinates (x,x^2+2x+1). The quadratic can be expressed as (x+1)^2.
Slope=m=∆y/∆x=(x^2+2x+1+2)/(x+1)=(x^2+2x+3)/(x+1).
When x=-0.90, m=20.1
When x=-1.05, m=-40.05
When x=h-1, m=(h^2-2h+1+2h-2+3)/h=(h^2+2)/h.
When h→0, m→h+2/h=∞ (infinity) The angle of slope approaches 90 degrees (vertical).