find the standard form of the equation of the parabola with the given characteristics and vertex at the origin focus:(0,6)

Question

please help me with the answer before tommorrow and show me step by step on how to solve it

Answer 1

Standard form is 4p(y-k)=(x-h)^2, where (h,k) is the vertex. If the vertex is at the origin (h,k)=(0,0). The focus is a distance p from the vertex, so p=6 in this case. Therefore 24y=x^2 is the equation. So y=x^2/24.