solve the equation (lnx)^2=ln(x^4)

solve the equation (lnx)^2=ln(x^4)

decimal form only ... round off answer to 1 decimal place
in Other Math Topics by Level 1 User (140 points)

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1 Answer

Let y=ln(x), then y²=4y, y(y-4)=0, so y=0=ln(x) and x=1; or y=4=ln(x) and x=e⁴=54.6 approx.

by Top Rated User (1.1m points)

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