solve sin(lnx)=1 for x

This is part of an 8 part question. I am supposed to find two values for x. One value is supposed to be e^(pi/2), but I don't understand how that could be.
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1 Answer

sin(ln(x))=1, so ln(x)=π/2+2πn=(4n+1)π/2, where n is an integer.

x=e(4n+1)π/2.

by Top Rated User (1.1m points)

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