A rectangle has a perimeter of 34 cm. Its length is 5 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.

Question

I need to find how to put the information given into a solving system equation and then solve the system by using elimination or substitution to find the dimensions of the rectangle.

Answer 1

we call W the width and L the length of the rectangle. So it is 34=2(L+W) (1) end L=2W+5 (2)

we plug the value of L from the(2) to (1) and we have. 34=2(2W+5+W) ---->>>>  34=2(3W+5)  --->>>

34=2(3W+5)   ---->>>  34=6W+10  --->>>  24=6W  and W = 4 cm  so from (2) we get  L=2*4+5 = 13 cm

check the perimeter is 2(4+13) = 2*17 = 34 cm