A lawn mower uses a fuel mixture of 23 parts gasoline to 1 part oil. How much gasoline should be added to a liter of a mixture that is 5 parts gasoline and 1 part oil?

Question

How would I go about setting up a table

Answer 1

1 liter of mixture contains 5 parts of gasoline and 1 part of oil. so we have a total of 6 parts. so each part

is 1000 ml / 6 parts = 166.66 ml / part

let x is the quantity of gasoline we must add in the mixture to make a mixture of 23 parts of gasoline

and 1 part of oil. So it will be  x + 5 * 166.66 = (x + 833.33) parts of gasoline and 1 part of oil

so it should be (x + 833.33) / 166.66 = 23 so x + 833.33 = 3833.18 so x = 3833.18 - 833.33 = 2999.85 ml

So 2999.85 ml of gasoline should be added in the mixture to get a mixture of 23 parts of gasoline to 1 part of oil.

Check; we have 2999.85 ml + 833.33 ml = 3833.18 ml of gasoline / 166.66 ml of oil = 23 this is the ratio

of parts of gasoline to parts of oil.