If (x+iy)^3=u+iv, Show that u/x+v/y=4(x^2-y^2)
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Expand the cube=x³+3ix²y-3xy²-iy³, so u=x³-3y² and v=3x²y-y³.

Therefore, u/x+v/y=x²-3y²+3x²-y²=4(x²-y²) QED
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