the population of 5000 fish is expected to increase by 12% each year. How many fish will there be in 15 years?algebra

Question

I need the equation that I’ll use. The initial amount, rate (as a decimal), growth or decay factor and what the x will be. Growth or Decay? The answer as well

Answer 1

Each year the growth factor will be (p+0.12p)/p=1.12 where p is the population at the beginning of a particular year. Therefore, after n years the growth is 1.12ⁿ. So the population will increase to 1.12ⁿp where p is the initial population.

If p=5000 and n=15 the increased population will be 1.12¹⁵×5000=27368 approximately.