Question

Complete and Balance the equations Ba(NO3)2 + Na3PO4

Answer 1

Let’s use the letters w, x, y, z to represent numbers:

wBa(NO₃)₂+xNa₃PO₄➝yBa₃(PO₄)₂+zNaNO₃

Now we can equate the letters:

w=3y (for Ba), 2w=z (for nitrate group NO₃), 3x=z (for Na) and x=2y (for phosphate group PO₄).

So, z=3x=2w=6y. The largest coefficient is 6, belonging to y, so let y=1, then z=6, x=2 and w=3.

That gives us:

3Ba(NO₃)₂+2Na₃PO₄➝Ba₃(PO₄)₂+6NaNO₃

This balances. I’m not a chemist so I don’t know if that’s how these chemicals would react but I guess the acid groups contain strong bonds that won’t be broken in the reaction.