What is the complete solution?
in Geometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

I assume the trapezoid is PQRS, not PRQS.

The angles at P, Q, M and D are all equal (congruent) because the trapezoid is isosceles and we have corresponding angles on a transverse between parallel lines. Therefore SMD=RQP, so 2(x+10)=5x-16.

Expanding: 2x+20=5x-16, 20+16=5x-2x, 36=3x, so x=12.

Now we know x we can find all the angles at the vertices:

Angles P and Q = 2(x+10)=44 degrees=5x-16 substituting x=12 degrees.

S and R are supplementary = 180-44=136 degrees.

 

 

by Top Rated User (1.1m points)

Related questions

0 answers
1 answer
1 answer
2 answers
asked Jan 7, 2012 in Geometry Answers by anonymous | 1.9k views
2 answers
asked Oct 7, 2014 in Other Math Topics by Scarlet | 823 views
4 answers
2 answers
asked Oct 6, 2011 in Geometry Answers by anonymous | 3.2k views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,806 answers
2,417 comments
523,398 users