PQRS is an isosceles trapezoid with median MD. If SP= 4(x-2) and RD= 6, what is x?

What is the value of RQ?
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I assume that median MD bisects SP at M and RQ at D, so RD=DQ=6, and RQ=12=RD+DQ.

SP=4(x-2), SM=MP and SP=RQ (because it’s an isosceles trapezoid), so SM=MP=6=½SP=2(x-1).

Therefore 2(x-1)=6, x-1=3, x=4.

by Top Rated User (1.1m points)

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