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What is the sum of the squares of the roots of $18x^2 +21x - 400$?

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asked May 16, 2019 in Algebra 1 Answers by anonymous

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1 Answer

First we need to find the roots (zeroes) of the quadratic 18x²+21x-400=(6x-25)(3x+16).

So the zeroes are 25/6 and -16/3. The sum of the squares is 625/36+256/9=(625+1024)/36=1649/36.

answered May 17, 2019 by Rod Top Rated User (1.1m points)

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