If AN bisects angle SAD, angle SAN= 2x- 3y, angle DAN=x+y, and the measure of angle SAD= 50 degrees, find the value of x and y.

Question

I'm having trouble understanding this problem in Honors Geometry. Help will be greatly appreciated!!!

Answer 1

SAN=DAN so 2x-3y=x+y, x=4y and x+y=50, so 4y+y=50, 5y=25 (half of SAD=50), y=5 and so x=20. SAN=2x-3y=40-15=25 and DAN=x+y=25, so the answers are confirmed.

Comments

Thank you!