A company produces two different types of 6-sided boxes. Box A is 12 inches long, 12 inches wide and 12 inches tall. Box B is 16 inches long, 16 inches wide and 6.75 inches tall. Both boxes have the same volume, but the company wants to know which box uses less product to make. A) Write and solve an expression to find the surface area of Box A. B) Write and solve an expression to find the surface area of Box B. C) Compare the box sizes. Which box uses less material?
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Box A is a cube with surface area=6×144=864 sq in, because each face has an area of 12²=144 sq in and there are 6 faces. An expression for the surface area is 6×12×12 (part A). Algebraically the surface area of a cube is 6a² where a is the side length.

Box B has a square top and bottom each 256 sq in, making 512 sq in in total. The four sides each have the same area: 16×6.75=108 sq in, so the total area for the 4 sides=4×108=432 sq in. The total surface area is 432+512=944 sq in.

(A cube always has the minimum surface area for maximum volume, compared with a cuboid or rectangular prism.) An expression for the surface area is 2×16²+4×16×6.75, which could be written 2×16(16+2×6.75) (part B); or algebraically, 2a(a+2h) where a is the square side and h the height.

(C) The most economical is Box A with SA 864 sq in, compared with Box B with SA 944 sq in.

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