A ball is thrown into the air with a speed of 32 feet per second The function h=32t-16t^2 models the height of the ball after t seconds How many seconds does it take for the ball to reach its maximum height?

 

 

MULTIPLE CHOICE:

 

A. 0.75 Seconds

B. 1 Second

C. 2 Seconds

D. 4 Seconds
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1 Answer

h=16(2t-t²)=16(1-1+2t-t²)=16(1-(t-1)²). When t=1, h is maximum at 16 feet. Answer B.

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