Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2

Question

write the numerical coefficient of each term to complete the required equation

Answer 1

y=(2+7x)/3 is another way of writing the given equation, and its gradient is 7/3, so the perpendicular gradient is -3/7.

Therefore since the perpendicular passes through (2,-5):

y=-(3/7)(x-2)-5, 7y=-3x+6-35=-3x-29.

3x+7y+29=0.

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