y=(x-2)(x+5) find axis of symmetry

y=(x-2)(x+5)

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1 Answer

y=x²+3x-10 is the expansion of the function.

We now complete the square:

y=x²+3x+9/4-9/4-10=(x+3/2)²-49/4.

This can be written y+49/4=(x+3/2)² which shows the vertex is at (-3/2,-49/4). The vertex is on the axis of symmetry, and is given by x=-3/2.

by Top Rated User (1.1m points)

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