If the area of Δ  804 2 with =43.2  and =38.7 , calculate two possible values for ̂, correct to one decimal place.
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I’m guessing that we have to find the included angle between two sides, given the area of the triangle, so we can use the area formula, ½absinθ=A. Therefore absinθ=804, 43.2×38.7sinθ=804, sinθ=804/(43.21×38.7)=0.9618 approx. There are two solutions for θ=74.1° and 105.9° because the sine of an angle is also the sine of its supplement.

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