Write an equation of the line parallel to y = -2x + 7

an equation of the line parallel to y = -2x + 7 that contains the point (2, -3).
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Write an equation of the line parallel to y = -2x + 7
an equation of the line parallel to y = -2x + 7 that contains the point (2, -3).

We need to determine the y-intercept of the new line. We
use y = mx + b, which we solve for b (b = y - mx). Plug in
the x and y values of the point we were given.

b = -3 - (-2 * 2)
b = -3 - (-4)
b = -3 + 4
b = 1

The equation we want is y = -2x + 1
by Level 11 User (78.4k points)

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