how high will a 42g ball rise with an initial speed of 15.6 m/s

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The mass is irrelevant, because inertial and gravitational mass are equivalent.

One equation is s=ut-½gt² , where u=15.6m/s, g=9.8m/s², t is time, s is vertical distance.

So s=15.6t-4.9t². This is a parabola, an upturned U, so its vertex is a maximum—maximum height.

This can be written s= -4.9(t²-(15.6/4.9)t).

We can complete the square:

s=-4.9(t²-(15.6/4.9)t+(7.8/4.9)²-(7.8/4.9)²),

s=-4.9((t-7.8/4.9)²-(7.8/4.9)²,

s=-4.9(t-7.8/4.9)² +7.8²/4.9.

The maximum height occurs when the parenthesised expression is zero that is when s=7.8²/4.9=12.4m approx.
by Top Rated User (1.1m points)

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