Find the sum of the following arithmetic series 1,2, 3…..99,100.

Find the sum of the following arithmetic series 1,2, 3…..99,100.

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1 Answer

Sn = n/2 [2a + (n-1)d]

where, a =1, d= 2-1 =1, n=100

So, Sn = 100/2 [2*1 + (100 -1)*1]

or Sn = 50[2+99] = 50 *101 = 5050

by Level 8 User (30.1k points)

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