T1+T2=-1 and T3+T4=-4. What are the first three numerical terms of this geometric sequence if r>0?
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1 Answer

Geometric progression is a, ar, ar2, ar3, ..., where a is the first term T1, and r is the common ratio.

T1+T2=-1, T3+T4=-4 so a+ar=-1=a(1+r); ar2+ar3=-4=ar2(1+r).

ar2(1+r)/(a(1+r))=-4/-1=r2 so r2=4, r=2 (r>0).

a(1+r)=3a=-1, a=-⅓.

GP=-⅓, -⅔, -1⅓, -2⅔, -5⅓, ... T1+T2=-⅓-⅔=-1;  T3+T4=-1⅓-2⅔=-4.

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