How do I solve systems of equations using substitution?

Question

solve for one variable(get it by itself on one side of the equal sign) ex. y= 2x-3
then plug it in (substitute it in where ever you see that variable) ex. x+y=2 becomes x+(2x-3)=2

example: -x+y=-2
2x+y=4
add x to both sides in the first problem
y=x-2
substitute that into the second problem
2x+(x-2)=4
combine like terms
3x-2=4
add 2 to both sides
3x=6 and divide by 3
x=2
then plug 2 into the origional problem (either one) for x
that will give you "y" in this case = 0

Answer 1

solve for one variable(get it by itself on one side of the equal sign) ex. y= 2x-3
then plug it in (substitute it in where ever you see that variable) ex. x+y=2 becomes x+(2x-3)=2

example: -x+y=-2
2x+y=4
add x to both sides in the first problem
y=x-2
substitute that into the second problem
2x+(x-2)=4
combine like terms
3x-2=4
add 2 to both sides
3x=6 and divide by 3
x=2
then plug 2 into the origional problem (either one) for x
that will give you "y" in this case = 0

Answer 2

How do you solve this system using substitution?

x=4y and 2x+3y=44