h(x) = x^3 - 2x^2 - 14x + 30

^ = the exponent of the power for the number given
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1 Answer

This can be solved using Newton's iteration method.

xn+1=xn-h(xn)/h'(xn) where the subscript denotes the iteration.

h'(x)=3x2-4x-14.

Let's start with x0=0 and find out the nearest zero.

x1=0-h(0)/h'(0)=0-30/-14=2.142857.

x2=2.142857-h(2.142857)/h'(2.142857)=2.217434...

x3=2.2205...., x4=2.2205... So we have one solution to the nearest hundredth.

We can use synthetic division to reduce the cubic to a quadratic to find the other two solutions.

2.2205...| 1 -2            -14             |   30

                1 2.2205...  0.4896...   |  -30

                1 0.2205... -13.5103... |    0 = x2+0.2205x-13.5103.

Using the quadratic formula x=3.5670 and -3.7876. So the three zeroes to the nearest hundredth are:

2.22, 3.57, -3.79.

by Top Rated User (1.1m points)

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