This can be solved using Newton's iteration method.
xn+1=xn-h(xn)/h'(xn) where the subscript denotes the iteration.
h'(x)=3x2-4x-14.
Let's start with x0=0 and find out the nearest zero.
x1=0-h(0)/h'(0)=0-30/-14=2.142857.
x2=2.142857-h(2.142857)/h'(2.142857)=2.217434...
x3=2.2205...., x4=2.2205... So we have one solution to the nearest hundredth.
We can use synthetic division to reduce the cubic to a quadratic to find the other two solutions.
2.2205...| 1 -2 -14 | 30
1 2.2205... 0.4896... | -30
1 0.2205... -13.5103... | 0 = x2+0.2205x-13.5103.
Using the quadratic formula x=3.5670 and -3.7876. So the three zeroes to the nearest hundredth are:
2.22, 3.57, -3.79.