f(x)= 4(x^2)(x+6)^2- State whether the graph crosses the x-axis or touches the x-axis and turns around
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

f(x) = 4(x^2)(x+6)^2

Find the zeroes:  x = 0, multiplicity 2, x = -6, multiplicity 2

Does the graph cross the x-axis?

No.  Each part- 4, x^2, and (x+6)^2- can never be negative, so f(x) can never be negative.

Does the graph touch the x-axis and turn around?

In other words, does f(x) ever equal zero (without becoming negative)?

Yes.  At x = 0 and x = -6.
by Level 13 User (103k points)

Related questions

1 answer
1 answer
0 answers
asked Apr 10, 2012 in Algebra 1 Answers by anonymous | 691 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,804 answers
2,417 comments
523,265 users