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5(2x-7)=33 -3(6x+4)

=10x-35=33-3(6x+4)

10x-35=33-18x-12

10x+18x=35+33-12

28x=68-12=56

x=56/28

=2
by

5(2x-7)=33-3(6x+4)

5(2x-7)=33-3(6x+4)

first you do the left side. USE DISTRIBUTIVE PROPERTY. you multiply 5 times 2x which =10x.(you have to leave the x bc you dont know what it is yet but you combine the #s you know first.) Then you multiply

10x-35=33-3(6x+4)

10x-35=33-3(6x+4)

Then do the same steps but do it do 3(6x+4). USE DISTRIBUTIVE PROPERTY.

10x-35=33-18x-12

since you have 2 #s that have x with it combine( add ) those two #s.

10x+18x=35+33-12

28x=68-12

28x=56

x=56 <-- NOT THE ANSWER! Now its simple algebra. you wanna get rid of the 28 so you have x alone. To do get rid of 28 is to add a -28.

-28+28x=56

That leave you with only x. But what you did to one side, you have to do to the other side. so do 56-28.

x=56-28

x=28

now all your left with is 28 so x=28!

Hope this helped with the explaining and everything.

 

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