Given: segment QK is congruent to sement QA; ray QB bisects < KQA

Prove: triabgle BQK is congruent to Triangle BQA
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In the two triangles side QB is common, and since QB bisects KQA, angles AQB and KQB are congruent. We are given that QA and QK are congruent so we have two congruent sides and a congruent included angle. This makes the triangles congruent.

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