-2x^4 + 5x^3 + 4x - 7
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Find zeroes of -2x4+5x3+4x-7?

When x=1, this becomes -2+5+4-7=0, so x-1 is a factor (x=1 is a zero).

Use synthetic division to divide by the zero:

1 | -2  5 0 4  -7

     -2 -2 3 3 | 7

     -2  3 3 7 | 0 = -2x3+3x2+3x+7.

The two graphs below show the original function in red and the above cubic function in blue. The red function intersects the x-axis at two points, one of which is x=1, the zero we found and the other is another zero, common to both functions at around x=2.6. A more accurate evaluation can be found using Newton's Iteration Method (not shown here). Using this method the zero is x=2.596715 to 6 dec places.

The remaining zeroes are complex numbers, which are -0.548358±1.023309i.

by Top Rated User (1.1m points)

Related questions

1 answer
1 answer
asked Oct 10, 2011 in Algebra 1 Answers by anonymous | 8.8k views
1 answer
1 answer
0 answers
asked Mar 7, 2013 in Algebra 1 Answers by anonymous | 1.1k views
3 answers
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,550 questions
99,628 answers
2,417 comments
440,773 users