find length and width of a rectangle that is 15 ft longer than it is wide and its area is 324 ft squared.

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Your answer

wbechem · Answer 1 · 2011-10-13T13:56:18+0000

lw =area

x(x+15)=324

x^2+15x-324=0

(x+27)(x-12)=0

x=12 feet, the width

x+15=27 feet, the length

robbins · Answer 2 · 2012-02-19T01:40:48+0000

find length and width of a rectangle that is 15 ft longer than it is wide and its area is 324 ft squared.

length = w +15

l*w = area

substitute

w*(w+15)=324

w^2 +15w -324=0

(w+27)(w-12)=0

width = 12 feet

so, length = 12 + 15= 27 feet

anonymous · Answer 3 · 2014-09-16T01:57:04+0000

the width of a rectangular field is 8m less than three times the length. If the perimeter is 312m find the length