y=2x^2-3x write in vertex form

Write the equation in vertex form. Identify the vertex.

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1 Answer

?????????? vertex form ????????

y=2x^2 -3x

=x(2x-3), so y=0 at x=0 & x=3/2

dy/dx=4x-3...slope

=0 at x=3/4...slope=0, so tangent is horizontal= lo point on kerv

=(0,-1.125)
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