if 1/3 of a machine's daily output is equal to 1/2 of another machine's daily output, and if the total day's output is 600 parts, how many parts were produced by the more efficient machine?
in order of operations by

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1 Answer

1. hav 2 masheens (x & y) that make 600 parts / dae

2. (x/3) =y/2

or y=(2/3)x

x+y=(5/3)x =600

x=600 /(5/3)

x=(3/5)*600=360

y=600-360=240
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