integral of (x^3 +1) (3x dx)

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1 Answer

I = Integral

I (x^3 + 1)(3xdx) =

u = x^3 + 1

du = 3xdx

I (x^3+1)3xdx = I (u)du = u^2/2 + c = (( x^3 + 1)^2)/2 + c
by Level 8 User (36.8k points)

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