There are three possible answers, although two not traditional ages for children.
abc=96.
b=a+2.
a(a+2)c=96.
(a^2+2a)c=96.
If a=0, there is no solution as abc=96.
If a=1, then b=3, and c=32, but 32 is not considered a child.
If a=2, then b=4, and c=12.
If a=3, then b=5 and c=32/5=6 and 2/5. not a traditional age.
If a=4, then b=6 and c=4, however b is the middle child.
Hence, a=2, b=4, and c=12 is the only "sensible" answer.