limits in calculus

1.limit as x approaches 0 of  sin 1/x  

2.limit as x approaches 0 of xsin1/x
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1 Answer

sine(1/x) at x gotu 0

sine(x)=x -x^3/3!+ more terms

so sine(1/x) =(1/x) -(1/3)*(1/x)^3 + more terms

as x gotu 0, sine(1/x) gotu + infinity

######

y=x*sine(1/x)... take first term oenlee & yu get (x/x)=1

as x gotu 0, y gotu 1
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