find f'(x) x(3x-1)^4

i need to find f'(x) at the given x value.

f(x)=x(3x-1) ; x=1  means f'(1)
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1 Answer

f(x) = x( 3x - 1) = 3x^2 - x

df/dx = 2*3x - 1 =  6x - 1

f'( 1) =6 * 1 - 1 = 5
by Level 8 User (36.8k points)

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