integarl of (cosx)^3sin2xdx
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sin(2x)=2sin(x)cos(x).

∫cos3(x)sin(2x)dx=2∫cos4(x)sin(x)dx.

Let u=cos(x), du=-sin(x)dx, sin(x)dx=-du.

-2∫u4du=-⅖u5+C=C-⅖cos5(x).

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