graphs of modulus function

I have some problem with graphs of modulus function.sad

Draw the graph of y=|x+2|+|x-3|

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1 Answer

The critical points are at x=-2 and x=3.

When -2≤x≤3 y=x+2-(x-3)=5. So between these values of x there is a horizontal line at y=5.

When x<-2, y=-(x+2)-(x-3)=-x-2-x+3=-2x+1.

When x>3, y=x+2+x-3=2x-1.

by Top Rated User (1.1m points)

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