consider a scenario where there are 3 red balls, 4 blue balls, and 5 white in a gambler's bag.

a gambler gives chances to the players that if they draw a red ball from his bag, they ein the jackpot, if they give a blue ball they win the second prize, and if they get a white ball then they loose.
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2 Answers

So basically you have 12 options. Red 1, Red 2, Red 3, Blue 1, Blue 2, Blue 3, Blue 4, White 1, White 2, White 3, White 4, and White 5. Each of these are worth 8.33%. Because there are 3 red balls, you multiply 8.33 by three, which equals 24.99, which is about 25%. So, you have a 25% chance of getting a red ball.
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TOTALLY THERE ARE 3+4+5=12 BALLS. WINNING EVENT MEANS TAKING A RED BALL FROM THE BAG. SO THE REQUIRED PROBABILITY = 3/12= 1/4
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