How many ways are there to give out the prizes?

A party has 6 different door prizes.  If there are 42 guests at the party and nobody is allowed to win more than one door prize, how many ways are there to give out the prizes?
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1 Answer

The number of ways of selecting 6 out of 42 guests is 5,245,786, using the nCr function for combinations.

The number of permutations of 6 door prizes is 6! (6*5*4*3*2*1)=720. Apply this permutation of prizes to each combination of 6 guests and we get 3,776,965,920. Wow! What a party!

by Top Rated User (1.1m points)

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