evaluate the integral:[sin^3(3x)cos(3x)] dx

evaluate the integral:[sin^3(3x)cos(3x)] dx
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Let u=sin(3x), du=3cos(3x)dx, so cos(3x)dx=du/3.

The integral becomes: ⅓∫u3du=u4/12 +C=sin4(3x)/12+C, where C is integration constant.

by Top Rated User (1.1m points)

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